Consolidate Result and rank structs

By not storing item index twice, we can cut down the size of Result
struct and now it makes more sense to store and pass Results by values.
Benchmarks show no degradation of performance by additional pointer
indirection for looking up index.
This commit is contained in:
Junegunn Choi committed 2017-07-18 03:14:33 +09:00
1 parent 5e72709613
commit bbe10f4f77
9 files changed
+65 -68

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+8 -8
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@@ -15,11 +15,11 @@ func assert(t *testing.T, cond bool, msg ...string) {
}
}
func randResult() *Result {
func randResult() Result {
str := fmt.Sprintf("%d", rand.Uint32())
return &Result{
item: &Item{text: util.RunesToChars([]rune(str))},
rank: rank{index: rand.Int31()}}
chars := util.RunesToChars([]rune(str))
chars.Index = rand.Int31()
return Result{item: &Item{text: chars}}
}
func TestEmptyMerger(t *testing.T) {
@@ -29,14 +29,14 @@ func TestEmptyMerger(t *testing.T) {
assert(t, len(EmptyMerger.merged) == 0, "Invalid merged list")
}
func buildLists(partiallySorted bool) ([][]*Result, []*Result) {
func buildLists(partiallySorted bool) ([][]Result, []Result) {
numLists := 4
lists := make([][]*Result, numLists)
lists := make([][]Result, numLists)
cnt := 0
for i := 0; i < numLists; i++ {
numResults := rand.Int() % 20
cnt += numResults
lists[i] = make([]*Result, numResults)
lists[i] = make([]Result, numResults)
for j := 0; j < numResults; j++ {
item := randResult()
lists[i][j] = item
@@ -45,7 +45,7 @@ func buildLists(partiallySorted bool) ([][]*Result, []*Result) {
sort.Sort(ByRelevance(lists[i]))
}
}
items := []*Result{}
items := []Result{}
for _, list := range lists {
items = append(items, list...)
}