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Consolidate Result and rank structs
By not storing item index twice, we can cut down the size of Result struct and now it makes more sense to store and pass Results by values. Benchmarks show no degradation of performance by additional pointer indirection for looking up index.
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9 files changed
+65
-68
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@@ -31,10 +31,10 @@ func TestOffsetSort(t *testing.T) {
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}
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func TestRankComparison(t *testing.T) {
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rank := func(vals ...uint16) rank {
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return rank{
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rank := func(vals ...uint16) Result {
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return Result{
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points: [4]uint16{vals[0], vals[1], vals[2], vals[3]},
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index: int32(vals[4])}
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item: &Item{text: util.Chars{Index: int32(vals[4])}}}
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}
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if compareRanks(rank(3, 0, 0, 0, 5), rank(2, 0, 0, 0, 7), false) ||
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!compareRanks(rank(3, 0, 0, 0, 5), rank(3, 0, 0, 0, 6), false) ||
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@@ -59,23 +59,23 @@ func TestResultRank(t *testing.T) {
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strs := [][]rune{[]rune("foo"), []rune("foobar"), []rune("bar"), []rune("baz")}
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item1 := buildResult(
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withIndex(&Item{text: util.RunesToChars(strs[0])}, 1), []Offset{}, 2)
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if item1.rank.points[0] != math.MaxUint16-2 || // Bonus
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item1.rank.points[1] != 3 || // Length
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item1.rank.points[2] != 0 || // Unused
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item1.rank.points[3] != 0 || // Unused
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if item1.points[0] != math.MaxUint16-2 || // Bonus
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item1.points[1] != 3 || // Length
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item1.points[2] != 0 || // Unused
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item1.points[3] != 0 || // Unused
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item1.item.Index() != 1 {
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t.Error(item1.rank)
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t.Error(item1)
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}
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// Only differ in index
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item2 := buildResult(&Item{text: util.RunesToChars(strs[0])}, []Offset{}, 2)
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items := []*Result{item1, item2}
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items := []Result{item1, item2}
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sort.Sort(ByRelevance(items))
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if items[0] != item2 || items[1] != item1 {
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t.Error(items)
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}
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items = []*Result{item2, item1, item1, item2}
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items = []Result{item2, item1, item1, item2}
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sort.Sort(ByRelevance(items))
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if items[0] != item2 || items[1] != item2 ||
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items[2] != item1 || items[3] != item1 {
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@@ -91,7 +91,7 @@ func TestResultRank(t *testing.T) {
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withIndex(&Item{}, 2), []Offset{Offset{1, 3}, Offset{5, 7}}, 5)
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item6 := buildResult(
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withIndex(&Item{}, 2), []Offset{Offset{1, 2}, Offset{6, 7}}, 6)
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items = []*Result{item1, item2, item3, item4, item5, item6}
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items = []Result{item1, item2, item3, item4, item5, item6}
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sort.Sort(ByRelevance(items))
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if !(items[0] == item6 && items[1] == item5 &&
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items[2] == item4 && items[3] == item3 &&
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