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Make is_package a function and call it consistently

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This commit is contained in:
Dave Halter
2019-12-01 19:31:31 +01:00
parent 6ffeea7eea
commit 8a26a23884
7 changed files with 19 additions and 10 deletions
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11
jedi/inference/value/module.py
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@@ -83,7 +83,7 @@ class SubModuleDictMixin(object):
package).
"""
names = {}
if self.is_package:
if self.is_package():
mods = iter_module_names(self.inference_state, self.py__path__())
for name in mods:
# It's obviously a relative import to the current module.
@@ -200,7 +200,7 @@ class ModuleValue(ModuleMixin, TreeValue):
self._path = file_io.path
self.string_names = string_names # Optional[Tuple[str, ...]]
self.code_lines = code_lines
self.is_package = is_package
self._is_package = is_package
def is_stub(self):
if self._path is not None and self._path.endswith('.pyi'):
@@ -224,8 +224,11 @@ class ModuleValue(ModuleMixin, TreeValue):
return os.path.abspath(self._path)
def is_package(self):
return self._is_package
def py__package__(self):
if self.is_package:
if self._is_package:
return self.string_names
return self.string_names[:-1]
@@ -235,7 +238,7 @@ class ModuleValue(ModuleMixin, TreeValue):
is a list of paths (strings).
Returns None if the module is not a package.
"""
if not self.is_package:
if not self._is_package:
return None
# A namespace package is typically auto generated and ~10 lines long.