Fix diff parser: If funcs are not copied, errors shouldn't either

This commit is contained in:
Dave Halter
2019-01-06 11:39:51 +01:00
parent 26aee1c6a9
commit 65b15b05e3
2 changed files with 48 additions and 14 deletions

View File

@@ -638,21 +638,23 @@ class _NodesTree(object):
working_stack = new_working_stack
had_valid_suite_last = True
elif (last_node.type in ('error_leaf', 'error_node') or
_is_flow_node(new_nodes[-1])):
# Error leafs/nodes don't have a defined start/end. Error
# nodes might not end with a newline (e.g. if there's an
# open `(`). Therefore ignore all of them unless they are
# succeeded with valid parser state.
# If we copy flows at the end, they might be continued
# after the copy limit (in the new parser).
# In this while loop we try to remove until we find a newline.
new_nodes.pop()
while new_nodes:
last_node = new_nodes[-1]
if last_node.get_last_leaf().type == 'newline':
break
if new_nodes:
last_node = new_nodes[-1]
if (last_node.type in ('error_leaf', 'error_node') or
_is_flow_node(new_nodes[-1])):
# Error leafs/nodes don't have a defined start/end. Error
# nodes might not end with a newline (e.g. if there's an
# open `(`). Therefore ignore all of them unless they are
# succeeded with valid parser state.
# If we copy flows at the end, they might be continued
# after the copy limit (in the new parser).
# In this while loop we try to remove until we find a newline.
new_nodes.pop()
while new_nodes:
last_node = new_nodes[-1]
if last_node.get_last_leaf().type == 'newline':
break
new_nodes.pop()
if new_nodes:
if had_valid_suite_last:

View File

@@ -852,3 +852,35 @@ def test_error_dedent_issues(differ):
differ.initialize(code1)
differ.parse(code2, parsers=5, copies=1, expect_error_leaves=True)
differ.parse(code1, parsers=1, copies=0)
def test_random_text_insertion(differ):
code1 = dedent('''\
class C:
def f():
return node
def g():
try:
1
except KeyError:
2
''')
code2 = dedent('''\
class C:
def f():
return node
Some'random text: yeah
for push in plan.dfa_pushes:
def g():
try:
1
except KeyError:
2
''')
differ.initialize(code1)
differ.parse(code2, parsers=1, copies=1, expect_error_leaves=True)
differ.parse(code1, parsers=1, copies=1)