From 7c1f3b3a65d2ffcdade411e9a65bad4c169f78d3 Mon Sep 17 00:00:00 2001 From: Dave Halter Date: Fri, 26 May 2017 14:19:06 -0400 Subject: [PATCH] Use escapes for some regex expressions. --- parso/grammar.py | 2 +- parso/utils.py | 2 +- 2 files changed, 2 insertions(+), 2 deletions(-) diff --git a/parso/grammar.py b/parso/grammar.py index 1e805f9..b48ae24 100644 --- a/parso/grammar.py +++ b/parso/grammar.py @@ -134,7 +134,7 @@ class Grammar(object): def _parse_version(version): - match = re.match('(\d+)(?:\.(\d)(?:\.\d+)?)?$', version) + match = re.match(r'(\d+)(?:\.(\d)(?:\.\d+)?)?$', version) if match is None: raise ValueError('The given version is not in the right format. ' 'Use something like "3.2" or "3".') diff --git a/parso/utils.py b/parso/utils.py index 1582f56..6ca3b2c 100644 --- a/parso/utils.py +++ b/parso/utils.py @@ -83,5 +83,5 @@ def version_info(): """ Version = namedtuple('Version', 'major, minor, micro') from parso import __version__ - tupl = re.findall('[a-z]+|\d+', __version__) + tupl = re.findall(r'[a-z]+|\d+', __version__) return Version(*[x if i == 3 else int(x) for i, x in enumerate(tupl)])