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builtins.sum: Items in the iterable must support addition with int if no start value is given (#8000)

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Alex Waygood
2022-06-13 11:25:38 +01:00
committed by GitHub
parent 7c473240ff
commit 1828ba2045
3 changed files with 67 additions and 7 deletions
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15
stdlib/builtins.pyi
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@@ -20,6 +20,7 @@ from _typeshed import (
SupportsKeysAndGetItem,
SupportsLenAndGetItem,
SupportsNext,
SupportsRAdd,
SupportsRDivMod,
SupportsRichComparison,
SupportsRichComparisonT,
@@ -1637,8 +1638,12 @@ def sorted(
@overload
def sorted(__iterable: Iterable[_T], *, key: Callable[[_T], SupportsRichComparison], reverse: bool = ...) -> list[_T]: ...
_SumT = TypeVar("_SumT", bound=SupportsAdd)
_SumS = TypeVar("_SumS", bound=SupportsAdd)
_AddableT1 = TypeVar("_AddableT1", bound=SupportsAdd[Any, Any])
_AddableT2 = TypeVar("_AddableT2", bound=SupportsAdd[Any, Any])
class _SupportsSumWithNoDefaultGiven(SupportsAdd[Any, Any], SupportsRAdd[int, Any], Protocol): ...
_SupportsSumNoDefaultT = TypeVar("_SupportsSumNoDefaultT", bound=_SupportsSumWithNoDefaultGiven)
# In general, the return type of `x + x` is *not* guaranteed to be the same type as x.
# However, we can't express that in the stub for `sum()`
@@ -1653,15 +1658,15 @@ else:
def sum(__iterable: Iterable[bool], __start: int = ...) -> int: ... # type: ignore[misc]
@overload
def sum(__iterable: Iterable[_SumT]) -> _SumT | Literal[0]: ...
def sum(__iterable: Iterable[_SupportsSumNoDefaultT]) -> _SupportsSumNoDefaultT | Literal[0]: ...
if sys.version_info >= (3, 8):
@overload
def sum(__iterable: Iterable[_SumT], start: _SumS) -> _SumT | _SumS: ...
def sum(__iterable: Iterable[_AddableT1], start: _AddableT2) -> _AddableT1 | _AddableT2: ...
else:
@overload
def sum(__iterable: Iterable[_SumT], __start: _SumS) -> _SumT | _SumS: ...
def sum(__iterable: Iterable[_AddableT1], __start: _AddableT2) -> _AddableT1 | _AddableT2: ...
# The argument to `vars()` has to have a `__dict__` attribute, so can't be annotated with `object`
# (A "SupportsDunderDict" protocol doesn't work)