Fix return type of email.header.decode_header() (#8337)

This commit is contained in:
Sebastian Rittau
2022-07-19 21:43:48 +02:00
committed by GitHub
parent 6903041744
commit 5534007189

View File

@@ -1,4 +1,5 @@
from email.charset import Charset
from typing import Any
__all__ = ["Header", "decode_header", "make_header"]
@@ -17,7 +18,10 @@ class Header:
def __eq__(self, other: object) -> bool: ...
def __ne__(self, __other: object) -> bool: ...
def decode_header(header: Header | str) -> list[tuple[bytes, str | None]]: ...
# decode_header() either returns list[tuple[str, None]] if the header
# contains no encoded parts, or list[tuple[bytes, str | None]] if the header
# contains at least one encoded part.
def decode_header(header: Header | str) -> list[tuple[Any, Any | None]]: ...
def make_header(
decoded_seq: list[tuple[bytes, str | None]],
maxlinelen: int | None = ...,