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make itertools.product more precise (#1393)

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This commit is contained in:
Matthias Kramm
2017-06-12 20:10:08 -07:00
committed by Jelle Zijlstra
parent ac36193550
commit ed6dc176da
2 changed files with 84 additions and 4 deletions
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38
stdlib/2/itertools.pyi
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@@ -93,9 +93,41 @@ def izip(iter1: Iterable[Any], iter2: Iterable[Any],
def izip_longest(*p: Iterable[Any],
fillvalue: Any = ...) -> Iterator[Any]: ...
# TODO: Return type should be Iterator[Tuple[..]], but unknown tuple shape.
# Iterator[Sequence[_T]] loses this type information.
def product(*p: Iterable[_T], repeat: int = ...) -> Iterator[Sequence[_T]]: ...
@overload
def product(iter1: Iterable[_T1]) -> Iterator[Tuple[_T1]]: ...
@overload
def product(iter1: Iterable[_T1],
iter2: Iterable[_T2]) -> Iterator[Tuple[_T1, _T2]]: ...
@overload
def product(iter1: Iterable[_T1],
iter2: Iterable[_T2],
iter3: Iterable[_T3]) -> Iterator[Tuple[_T1, _T2, _T3]]: ...
@overload
def product(iter1: Iterable[_T1],
iter2: Iterable[_T2],
iter3: Iterable[_T3],
iter4: Iterable[_T4]) -> Iterator[Tuple[_T1, _T2, _T3, _T4]]: ...
@overload
def product(iter1: Iterable[_T1],
iter2: Iterable[_T2],
iter3: Iterable[_T3],
iter4: Iterable[_T4],
iter5: Iterable[_T5]) -> Iterator[Tuple[_T1, _T2, _T3, _T4, _T5]]: ...
@overload
def product(iter1: Iterable[_T1],
iter2: Iterable[_T2],
iter3: Iterable[_T3],
iter4: Iterable[_T4],
iter5: Iterable[_T5],
iter6: Iterable[_T6]) -> Iterator[Tuple[_T1, _T2, _T3, _T4, _T5, _T6]]: ...
@overload
def product(iter1: Iterable[Any],
iter2: Iterable[Any],
iter3: Iterable[Any],
iter4: Iterable[Any],
iter5: Iterable[Any],
iter6: Iterable[Any],
iter7: Iterable[Any], *iterables: Iterable) -> Iterator[Tuple]: ...
def permutations(iterable: Iterable[_T],
r: int = ...) -> Iterator[Sequence[_T]]: ...