Find the ';"' that ends an address by reading the address

Taking the first ';"' before a tab could land inside the pattern: a line holding
';"' followed by a tab, such as a comment, cut the address there and left the
real tab unescaped, so the entry was refused.

autoload/fzf/vim.vim

@@ -547,7 +547,6 @@ function! s:sandboxed(cmd)
   return 'sandbox execute '.string(a:cmd)
 endfunction
 
-
 " Address of a tag, given the rest of the line after the file name, or, with
 " 'whole' off, the address field alone as :BTags reads it. Only the forms a tags
 " file is meant to hold, a line number and a search pattern, chained with ';' for
@@ -1659,7 +1658,8 @@ endfunction
 " ';"' terminator says where the address ends, so a line without one is left as
 " it is rather than guessed at
 function! s:tabs_in_address(line)
-  return substitute(a:line, '^\%([^\t]*\t\)\{2}\zs.\{-}\ze;"\t',
+  return substitute(a:line, '^\%([^\t]*\t\)\{2}\zs'.s:tag_address_part
+        \ .'\%(;'.s:tag_address_part.'\)*\ze;"\t',
         \ '\=substitute(submatch(0), "\t", ''\\t'', "g")', '')
 endfunction