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Turn uidl() into an overload. (#1231)

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The previous change was still right. Unique among `poplib` functions, `uidl()` returns a long response when called without arguments, but just a bytes string when called with a `which` argument.
This commit is contained in:
Guido van Rossum
2017-05-01 08:56:27 -07:00
committed by GitHub
parent 464761bfd3
commit b6a9a05743
1 changed files with 7 additions and 2 deletions
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9
stdlib/2and3/poplib.pyi
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@@ -4,7 +4,7 @@ from mypy_extensions import NoReturn
import socket
import ssl
import sys
from typing import Any, BinaryIO, Dict, List, Optional, Pattern, Text, Tuple
from typing import Any, BinaryIO, Dict, List, Optional, overload, Pattern, Text, Tuple
_LongResp = Tuple[bytes, List[bytes], int]
@@ -49,7 +49,12 @@ class POP3:
else:
def apop(self, user: Text, password: Text) -> bytes: ...
def top(self, which: Any, howmuch: int) -> _LongResp: ...
def uidl(self, which: Optional[Any] = ...) -> _LongResp: ...
@overload
def uidl(self) -> _LongResp: ...
@overload
def uidl(self, which: Any) -> bytes: ...
if sys.version_info >= (3, 5):
def utf8(self) -> bytes: ...
if sys.version_info >= (3, 4):